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What would happen if my speeds are equal to the drift velocity and in a second case close to the speed of light

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- Thread starter quawa99
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- #1

- 67

- 2

What would happen if my speeds are equal to the drift velocity and in a second case close to the speed of light

- #2

Khashishi

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If you move near the speed of light, then both electrons and ions are moving backwards in your frame of reference at close to the speed of light. It is necessary to transform the 4-current, which is

##J^\alpha = (c \rho, j)##

What is the four-current in the frame moving at v/2?

Assume total charge in this frame is 0.

The current is -nv/2 - nv/2

so the four-current is

##J_1 = (0, -nv)##

Let u = your velocity relative to the frame moving at v/2.

Using Lorentz transformation,

##J_2 = (\gamma uvn/c, \gamma nv)##

The current density is much greater in your frame, by a factor of ##\gamma##, and there is a charge density as well. But the length of the conductor will also be contracted by a factor of ##\gamma##, so the total current is the same. In this frame, there will be an electric field as well as a magnetic field.

You can look at it two ways. The electric field arises from a Lorentz transformation of the magnetic field in the original frame. Or the electric field arises from the charge which results from a Lorentz transformation of the current in the original frame. Same thing.

- #3

Simon Bridge

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Since the drift velocity is typically much smaller than lightspeed in the frame of the wire, you wouldn't see big effects from the difference between the speeds (moving charges and wire) in your frame.

The usual way to treat these problems is to model the wire as two lines of charges... decide on a frame of reference and the charge densities in that frame.

Very important - if "you" are the observer, do not talk about "you" moving.

Everything else is moving. "You" are always stationary.

Reword the question with these things in mind and you should find it easier to cope with.

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